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21 December, 19:40

Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building?

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  1. 21 December, 19:56
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    Since his line of sight 63 degrees makes with the tip of the building

    Tan63° = height of building / Horizontal distance

    tan63° = Height / 50

    50tan63° = Height

    Height = 50tan63°

    Height ≈ 50*1.9626

    Height ≈ 98.13 m

    Height of the building is ≈ 98.13 m. Mind you in solving for this height we have neglected the height of Daniel.

    The height of building actually should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.
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