F (x) = x + 6 In the function above, b is a constant. If f (6) = 7,

what is the value of f (-2) ?

A) 5

B) - 2

C)

D)

1

7

f (-2) = 1

(assuming you meant "f (x) = x + b" in the first line)

Explanation:

Given: f (x) = x + b

plug in (6,7)

f (6) = 6 + b

7 = 6 + b

b = 1

so the equation is f (x) = x + 1

plug in x = - 2

f (-2) = x + 1 = - 2 + 1 = 1