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1 October, 22:07

How many grams of CaCl2 (molar mass = 111g/mol) are needed to prepare 100. mL of 0.100MCl - (aq) ions?

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  1. 2 October, 00:19
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    Answer: 1.11 grams

    Explanation:

    1.11g/111 M =.01

    100mL =.1 L

    .01/.1 =.1
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