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4 September, 17:05

What is a solution for the equation 2-3^-x=-1

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  1. 4 September, 20:12
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    x = - ln 5 / ln 3

    Explanation:

    2-3^-x=-1

    -3^-x=-5 (Subtract two from each side)

    3^-x=5 (Divide by - 1)

    -x (ln 3) = ln 5 (Take the natural log of each side, - x comes down to the front)

    -x=ln 5 / ln 3

    x = - (ln 5 / ln 3) - -> x = - ln 5 / ln3
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