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18 April, 09:11

The floor of a rectangular deck has a length that is 6 feet more than it's width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?

A. x^2 + 12x + 27

B. x^2 + 9x + 18

C. x^2 + 9x

D. x^2 + 6x

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  1. 18 April, 11:07
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    The correct Answer is A. x^2 + 12x + 27

    Width of floor = w = x

    Length of floor = l = x + 6

    New dimesions are increase by three so our

    W = x + 3

    L = x + 6 + 3 = > L = x + 9

    As we know that Area = width*length so

    area = W * L

    = (x + 3) * (x + 9)

    = x∧2 + 9x + 3x + 27

    = x∧2 + 12x + 27

    Which is our option A.
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