How do you do a dihybrid cross with an autosomal and sex linked trait?

Genotype of woman: Bb X^C X^c

Genotype of man: bb X^C Y

Probability of brown eyes = 1/2

Probability of colorblind male = 1/4

Probability of brown-eyed colorblind male = 1/2 X 1/4 = 1/8

2. Genotypes are the same as before. You know the fetus is a boy. So, he has a 50% chance of being colorblind.