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17 March, 19:00

Consider the following cross:

Parent 1: YyTt

Parent 2: YyTt

Using the rules of probability, determine the probability that the offspring will show YyTT genotype?

A.) 1

B.) 8

C.) 16

D.) 2

+3
Answers (1)
  1. 17 March, 20:32
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    The probability that the offspring will show YyTT genotype is 1/16. To solve for this, the Punnet Square must be used. All possible allele combinations are then shown. Both parents show two traits making the Punnet Square have four columns and four rows.
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