Ask Question
24 March, 00:37

In a population with two alleles, B and b, the allele frequency of B=0.59. What would be the frequency of the heterozygotes if the population is in Hardy-Weinberg equilibrium?

+1
Answers (1)
  1. 24 March, 01:25
    0
    0.483

    Explanation:

    The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.

    Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f (B) + f (b) = 1

    If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59 = 0.41

    The frequency of heterozygous genotype in the population = 2pq

    p = frequency of the dominant allele

    q = frequency of the recessive allele

    So, 2pq = 2 x 0.59 x 0.41 = 0.483
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In a population with two alleles, B and b, the allele frequency of B=0.59. What would be the frequency of the heterozygotes if the ...” in 📙 Biology if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers