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2 September, 13:44

In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherless legs. How many chickens are heterozygous for the "feathered leg" allele? Assume the population is in Hardy-Weinberg equilibrium.

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  1. 2 September, 17:10
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    64

    Explanation:

    Since the population is in Hardy-Weinberg equilibrium and the equilibrium is defined by the equation

    p² + 2pq + q²

    where the frequency of the homozygous dominant allele F (feathers on the leg) = p²,

    F of homozygous (featherless legs) = q²

    F of heterogyous (carrier of featherless allele) = 2pq

    F (q²) = 128/200 = 0.64

    q = √0.64 = 0.8

    and p + q = 1

    p = 1 - 0.8 = 0.2

    2pq = 2 * 0.2 * 0.8 = 0.32

    number of chickens that are heterozgous for the feathered leg allele = 0.32 * 200 = 64
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