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5 June, 00:45

1. Cross one parent that is heterozygous for both beak color and feather color with a parent that is homozygous for both recessive traits. What are the genotypes of the parents? (Hint: Recall that the P generation includes a heterozygous parent with dominant traits and a homozygous parent with recessive traits.)

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  1. 5 June, 01:06
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    Heterozygous AaBb

    Homozygous recessive aabb

    Explanation:

    Parental genotypes are what alleles the parents have.

    Let beak color be A/a

    Let feather color be B/b

    Since one parent is heterozygous for both beak color and feather color, they would have genotype of AaBb

    Since one parent is homozygous recessive for both beak color and feather color, they would have genotype of aabb
  2. 5 June, 04:07
    0
    Y = dominant for feather, y = recessive for feather

    B = dominant for beak, b = recessive for beak

    Homozygous for both alleles for dominant traits = YYBB

    Homozygous for both alleles for recessive traits = yybb

    Heterozygous for both allels = YyBb

    In the case you mentioned one parent (Parent 1) is heterozygous for both traits so it is YyBb

    The other parent (Parent 2) is homozygous for both traits so it is yybb

    The gamets for Parent 1 are YB, Yb, yB, yb

    The gamets for Parent 2 are yb

    When they are crossed the following genotypes are for the F1.

    Parent 1 ... YB ... Yb ... yB ... yb

    Parent 2 ... yb ... yb ... yb ... yb

    F1 ... YyBb ... Yybb ... yyBb ... yybb
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