Suppose that the eye color and wing shape genes assort independently (they are not linked, i. e., they are located on different chromosomes). In a mating between a female with the genotype w+m+/wm and a male of genotype wm/wm what percentage of the F1 progeny will have a non-parental genotype?

Question

Biology

Bear

23 September, 01:16

Suppose that the eye color and wing shape genes assort independently (they are not linked, i. e., they are located on different chromosomes). In a mating between a female with the genotype w+m+/wm and a male of genotype wm/wm what percentage of the F1 progeny will have a non-parental genotype?

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Answers (1)

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Odin Durham · Answer 1

w+m+/wm x wm/wm = 1/2 w+m+/wm + 1/2 wm/wm

The percentage will be 50%

Explanation:

If the genes are not linked, the frecuency will have 1/2 (50%) because it is the probability of segregation in the second meiotic division