Two genes are 22 map units apart on the same chromosome. A true-breeding GGhh individual is crossed to a true-breeding ggHH individual. The F1 offspring are mated to gghh individuals. If this testcross produces 1000 offspring, how many of them would you expect to be GgHh?

Select one:

a. 390

b. 250

c. 220

d. 110

Question

Biology

Gauge Shah

6 February, 10:42

Two genes are 22 map units apart on the same chromosome. A true-breeding GGhh individual is crossed to a true-breeding ggHH individual. The F1 offspring are mated to gghh individuals. If this testcross produces 1000 offspring, how many of them would you expect to be GgHh?

Select one:

a. 390

b. 250

c. 220

d. 110

+1

Answers (1)

Know the Answer?

Ruben Cochran · Answer 1

d. 110

Explanation:

Parental cross: Gh/Gh x gH/gH

F1: Gh/gH

The following test cross experiment is done:

Gh/gH x gh/gh

Gametes produced by these individuals:

- gh/gh: gh (probability of 1)

- Gh/gH:

Gh (parental) gH (parental) GH (recombinant) gh (recombinant)

The formula that relates genetic distance with recombination frequency is:

Genetic Distance (m. u.) = Recombination Frequency X 100

In this problem:

22 m. u. / 100 = Recombination Frequency

0.22 = Recombination Frequency

The recombination frequency altogether is 0.22, but there are 2 possible types of recombinant gametes and when one is generated, the other one is generated as well. Therefore, each recombinant gamete has a frequency of half the total recombination frequency: 0.11

In an offspring of 1000 individuals, I would expect 110 to be GH/gh.