How much thermal energy needs to be added to 0.455 kg of benzene to heat it from 30*c to 50*c

15834 joules is the thermal energy required.

Explanation:

Specific heat capacity of benzene = 1.74 J/gK or 1740 J/Kg K

mass of benzene = 0.455 kg

temperature change = 50-30

= 20 degrees

From the formula:

Specific heat capacity = thermal energy / (mass) * (temperature change)

thermal energy = 0.455 * 1740*20 (speicfic heat of benzene is converted

to joules per gram)

= 15834 joules