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23 April, 15:37

Use the Punnet Squares interactive, Level 3 to conduct a cross between a man with normal vision and a woman with the gene for color blindness. A man with normal vision, XB Y, and a woman who is a carrier for color blindness, XB Xb, mate. How many total phenotypes result from this cross? number of phenotypes: What percentage of male offspring will be color‑blind? color‑blind male offspring: % If the father were color‑blind, what percentage of male offspring would be color‑blind? color‑blind male offspring:

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  1. 23 April, 19:14
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    Answer: 1) The resulting phenotypes are: Woman and man with normal vision, woman with normal vision and carrier for the color blindness and man with color blindness.

    2) 25% (1/4) man with color blindness.

    3) 25% (1/4) man with color blindness.

    Explanation: For the cross a woman carrier for color blindness and a man with normal vision, the resulting phenotypes are: 1) woman with normal vision (25%), 2) Woman carrier of the mutation (25%), 3) man with normal vision (25%), 4) man with color blidness (25%).

    For the cross a woman carrier for color blindness and a man with color blindness, the resulting phenotypes are: 1) woman with color blindness (25%), 2) Woman carrier of the mutation (25%), 3) man with normal vision (25%), 4) man with color blidness (25%).
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