If a population with two alleles is at Hardy-Weinberg equilibrium ad the frequency of one allele is 0.7, what is the heterozygote frequency?

A. 0.7B. 0.42C. 0.3D. 0.21E. insufficient information given to answer the question

B. 0.42

Explanation:

Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1

According to the given information, the frequency of one allele in the population is = 0.7

This means that the frequency of the other allele would be = 1-0.7 = 0.3

Frequency of heterozygote in the population = 2pq = 2 x 0.7 x 0.3 = 0.42