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24 February, 11:56

What is the Reynolds number for blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 * 10-3 Pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 15.9 cm/s?

The blood flow through the aorta in the given scenario is:

a) turbulen

b) laminar

c) transitioning between laminar and turbulen.

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  1. 24 February, 13:26
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    b. laminar flow

    the reynold number is 1329.26

    Explanation:

    Re = (V x D x ρ) / η

    where,

    V = mean velocity = 15.9 cm/s = 0.159m/s

    D = vessel diameter = 2.15cm = 0.0215m

    ρ = blood density = 1050 kg/m3 = 0.00105 kg/cm3

    η = dynamic viscousity = 2.70 * 10-3 Pa·s = 2.70 * 10-3 kg/m-s

    applying the formular to calculate for reynolds number, Re =

    Re = (V x D x ρ) / η

    = (0.159 x 0.0215 x 1050) / 2.70 * 10-3

    =3.589/0.0027 = 1329.26

    the Reynolds number for the blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 * 10-3 Pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 15.9 cm/s is 1329.26

    which flow through the aorta in a Laminar flow

    Note that

    a) turbulen = Re >4000

    b) laminar = Re <2300

    c) transitioning between laminar and turbulen = Re between 2100 and 4000
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