The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side B is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal.

Question

Biology

Malcolm Mcdaniel

26 June, 20:23

The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side B is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal.

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Answers (1)

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Olsen · Answer 1

Intially the glucose concentration is levelled and then the liquid level in side A will rise.

Explanation:

Initially the liquid ob both sides are in isotonic condition. The membrane is permeable to glucose so glucose will diffuse from higher concentration (2 M) to lower concentration (1 M) until the concentration become equal (1.5 M) on both sides. Know, the Side A have 2 M sucrose and 1.5 M glucose and side B have 1 M glucose and 1 M sucrose. The side A will become hypertonic and side B will become hypotonic and water will start moving from side B to side A.