If an individual homozygous dominant for widow's peak has a child with an individual heterozygous for widow's peak, what is the chance that the child will have a widow's peak?

100%

Explanation:

Let PP represent homozygous dominant trait for widow's peak &

Let Pp represent an individual heterozygous for widow's peak.

If both traits cross together; the chance that the child will have a widow's peak = ?

i. e PP * Pp

| P | P

P | PP | PP

p | Pp | Pp

The progeny are: (PP, PP, Pp, Pp)

When a trait is dominant, only one allele is required for the trait to be observed. A dominant allele will mask a recessive allele, if present.

From our question, one parent is homozygous dominant (PP) and the other is heterozygous (Pp) : therefore all their offspring will be two homozygous dominant (PP) and two heterozygous (Pp) and they will all possess a widow's peak.

Therefore, the chance that a child will have a widow's peak = 100%