In the 1950s, Christian Anfinsen demonstrated the renaturation of the protein ribonuclease (RNase) in vitro. After reduction (to reduce the disulfide links) and the addition of urea (to denature the protein), the protein was in an unfolded state. After removing the urea and the reducing agent, the protein refolded, with greater than 90% activity. If the urea were removed after oxidation occurred, the protein had less than 5% activity. Why would the protein not refold correctly if the urea were removed after the reducing agent was removed? (In other words, what would happen if the urea were removed after oxidation?) Choose the best answer. a. Urea would participate in weak bonding interactions with RNase, preventing oxidation of Cys. b. The protein would not fully unfold (denature). c. Disulfide bonds are not positioned correctly unless weak bonding interactions are present. d. Contaminants in the RNase preparation would form covalent bonds with the protein, preventing reactivation.

Question

Biology

Buchanan

26 January, 13:39

In the 1950s, Christian Anfinsen demonstrated the renaturation of the protein ribonuclease (RNase) in vitro. After reduction (to reduce the disulfide links) and the addition of urea (to denature the protein), the protein was in an unfolded state. After removing the urea and the reducing agent, the protein refolded, with greater than 90% activity. If the urea were removed after oxidation occurred, the protein had less than 5% activity. Why would the protein not refold correctly if the urea were removed after the reducing agent was removed? (In other words, what would happen if the urea were removed after oxidation?) Choose the best answer. a. Urea would participate in weak bonding interactions with RNase, preventing oxidation of Cys. b. The protein would not fully unfold (denature). c. Disulfide bonds are not positioned correctly unless weak bonding interactions are present. d. Contaminants in the RNase preparation would form covalent bonds with the protein, preventing reactivation.

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Answers (1)

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Camille Stanley · Answer 1

c. Disulfide bonds are not positioned correctly unless weak bonding interactions are present.

Explanation:

Urea unfolds the protein by forming weak non-covalent bonds with the polpeptide and because it forms stronger van der Waals interactions with the polpeptide than water it is able to unfold the protein. Removing the reducing agent before removing urea would cause mismatch of the Cysteine disulfide bonding. This is because the polypeptide chain would not be fully unfolded and be able to follow its correct/natural trajectory it requires to fold properly.