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13 July, 00:01

You observe that the frequency of the AB haplotype at the A and B loci is 0.558 in a population. You also observe that the frequency of the A allele at the A locus is 0.887 while the frequency of the B allele is 0.396. What is the coefficient of linkage disequilibrium (give your answer to three decimal places)

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  1. 13 July, 01:27
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    D = 0.207

    Explanation:

    Coefficient of the linkage disequilibrium

    D = hAB - fAfB

    Where,

    D is the difference between the actual frequency of the AB haplotype (hAB) and the expected frequency of AB (given independent) = > (fA * fB)

    D = 0 means that the alleles are not associated

    => Varies from - 0.25 to 0.25

    Given,

    Two haplotypes

    hAB = 0.558

    Frequency of allele A (fA) = 0.887

    Frequency of allele B (fB) = 0.396

    D = hAB - fAfB

    = (0.558) - (0.887 * 0.396)

    = 0.558 - 0.351252

    = 0.206748

    D = 0.207 (approx. 3 decimal places).
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