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24 September, 08:06

For an enzyme catalyzed reaction at equilibrium, what is the K if the concentrations of product is 0.5 mM and concentration of substrates are 6.5 mM and 3.0 mM?

a) 3.9x 10

b) 2.56 x 10

c) 167

d) 25.6

e) 2560

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Answers (1)
  1. 24 September, 10:51
    0
    d) 25.6

    Explanation:

    K = [0.5 e-3] / [6.5 e-3 x 3.0 e-3]

    = 0.0256

    = 25.6
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