Fragile X syndrome is an X-linked dominantly inherited condition that contributes to autism and intellectual inabilities. Two individuals mate and produce three children. The female is heterozygous for the condition, and the male also displays the condition. What is the probability that the first two children will have the disorder and the last child will not?

The probability for the given scenario will be 9/64

Explanation:

As indicated by the above expressed inquiry,

Two people (i. e) male (hetero) + female (hetero)

Prevailing + Latent = First Child

Latent + Dominan = Second Child

Latent + Passive = Third Child

The probability of gene communicating will be low than initial two children. The coding succession is called codons ... There are 64 codons for each 3 grouping one amino-acid will be produced. The likelihood of prevailing gene will be 9.

So the appropriate response is 9/64.