the no grouse allele is dominant over the grouse allele. if a pigeon homozygous for the no grouse allele mates with a heterozygours pigeon, what is the expected frequency of the feathery-legged (grouse phenotype in the offspring

1/2 or 50%

Explanation:

The expected frequency of the feathery-legged (grouse phenotype) in the offspring is 1/2 or 50%.

Let the no grouse allele be represented by A (dominant).

Let the grouse allele be represented by a (recessive).

For a pigeon that is homozygous for grouse allele, the genotype will be aa.

For a pigeon that is heterozygous, the genotype will be Aa.

Crossing Aa with aa:

Aa x aa

Aa Aa aa aa

% Aa - no grouse = 50%

% aa - grouse = 50%

Hence, the expected frequency of the feathery-legged (grouse phenotype) in the offspring is 1/2 or 50%.