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18 January, 11:57

In humans, red-green color blindness is determined by an X-linked recessive allele (a), whereas eye color is determined by an autosomal gene, where brown (B) is dominant over blue (b). If a blue-eyed mother with normal vision has a brown-eyed, color-blind son and a blue-eyed, color-blind daughter, what are the genotypes of both parents and children

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  1. 18 January, 15:56
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    Mother - bb XAXa

    Father - Bb XAY

    Son - Bb XaY

    Daughter - bb XAXa

    Explanation:

    Given -

    Mother has blue-eye and normal vision

    Son has brown eye and is color blind

    Let the allele for Blue eye be represented by "b" and the allele for brown eye be represented by "B"

    Given brown (B) is dominant over blue (b), thus both BB and Bb represents brown color eyes

    Color blindness is associated with X gene

    Thus Xa represents X - linked recessive colorblindness

    And XA represents normal vision

    Genotype of blue-eye and normal vision mother is bb XAXa. Mother is the carrier of recessive allele Xa for color blindness

    Since son is color blind, his genotype would be Bb XaY

    So fathers genotype would be

    Bb XAY

    Daughters genotype bb XAXa
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