In the previous question, you used the Hardy-Weinberg equation to determine the frequencies of the genotypes for HH, Hh, and hh, given gene frequencies of H = 0.2 and h = 0.8. These frequencies were: HH = 0.04 Hh = 0.32 hh = 0.64 Now, determine the expected numbers of each organism in the population (total size = 150) : Number of HH = Number of Hh = Number of hh =

Question

Biology

Jerimiah Phelps

27 October, 19:21

In the previous question, you used the Hardy-Weinberg equation to determine the frequencies of the genotypes for HH, Hh, and hh, given gene frequencies of H = 0.2 and h = 0.8. These frequencies were: HH = 0.04 Hh = 0.32 hh = 0.64 Now, determine the expected numbers of each organism in the population (total size = 150) : Number of HH = Number of Hh = Number of hh =

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Answers (2)

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Buffie · Answer 1

HH - 6

Hh - 48

hh-96

Cujo · Answer 2

If frequencies are: HH = 0.04 Hh = 0.32 hh = 0.64, this expressed in the percentage is 4%, 32% and 64% (4+32+64=100) respectively. If the total number of organisms in population is 150 then:

Number of organisms with HH genotype is 0.4*150 = 6

Number of organisms with Hh genotype is 0.32*150=48

Number of organisms with hh genotype is 0.64*150=96

6+48+96=150