If all of the oxaloacetate (OAA) in the cell was consumed, say by an intracellular pathogen that eats OAA as its primary food source, how would it affect the activity of the Citric Acid Cycle? The Citric Acid Cycle would slow because OAA is a reactant. It would increase activity because OAA is a product (Le Chatelier's principle). It wouldn't affect it at all because OAA is both a reactant and product of the Cycle.

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Biology

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4 August, 10:03

If all of the oxaloacetate (OAA) in the cell was consumed, say by an intracellular pathogen that eats OAA as its primary food source, how would it affect the activity of the Citric Acid Cycle? The Citric Acid Cycle would slow because OAA is a reactant. It would increase activity because OAA is a product (Le Chatelier's principle). It wouldn't affect it at all because OAA is both a reactant and product of the Cycle.

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Jayden Rasmussen · Answer 1

The Citric Acid Cycle would slow because oxaloacetate (OAA) is a reactant.

Explanation:

1. The citric acid cycle also known as the TCA (tricarboxylic acid cycle) cycle.

2. It is also known as Krebs cycle because the scientist Krebs.

3. It is a series of chemical reactions required many enzymes and is used to release stored energy through the oxidation of acetyl-CoA.

4 In Krebs cycl, oxaloacetate react with acetyl CoA, to form citrate, if all of the oxaloacetate in the cell are consumed, then the Krebs cycle would slow down because without oxaloacetate, TCA cycle can not proceed and acetyl CoA can not directly enter TCA cycle.