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28 August, 10:39

You have a culture of yeast that is at a concentration of 6.74 x 10^6 cells/ml. You dilute the sample 1:100, and then 1:100 again, and finally you dilute the sample an additional 1:3. You add 0.1 ml of the final dilution to a spread plate.

1. Assuming that most of the cells in the original culture were living, how many CFUs do you expect to count on your spread plate the next day?

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  1. 28 August, 11:43
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    22 cells

    Explanation:

    The concentration of numbers of cells = 6.74 x 10⁶ cells/ml

    Dilution stages includes = 1:100; 1:100 & 1:3

    The consecutive dilution stages can be calculated as:

    = (6.74 x 10⁶) * (1/100) (1/100) (1/3)

    = 222.42 cells/ml

    = 2.22 * 10² cells/ml

    So after addition 0.1 ml of the final dilution to a spread plate, the number of CFUs (Colony forming units) we expect to count will be:

    = (2.22 * 10² cells/ml) (0.1 ml)

    = 22.2 cells

    ≅ 22 cells.
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