Consider a population of fish in which two stripe patterns are observed, a single stripe or no stripes. A single stripe, S, is dominant to no stripes, s. After monitoring this population closely for 10 generations, it is determined that the allele frequency for S is 0.75 and the allele frequency for s is 0.25 and it has not changed within the observation period. If you assume that Hardy-Weinberg equilibrium estalished, indicate the expected frequency of each genotype based on the equation for Hardy-Weinberg equilibrium.

The equation for Hardy-Weinberg equilibrium states that at a locus with two alleles, as in this flower population, the three genotypes will occur in specific proportions:

p^2 + 2pq + q^2 = 1

Required:

a. What is the genotype frequency for SS fish?

b. What is the genotype frequency for Ss fish?

c. What is the genotype frequency for ss fish?

Question

Colten Bell

10 May, 01:57

+1

Answers (1)

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Declan Pruitt · Answer 1

Q*1 P * 0.15 Q=0.25

SS frecuency = 0.15*0.15=0.5625

Ss frecuency = 0.15*0.25 = 0.1515

ss frecuency = 0.25 * 0.25=0.0625