Ask Question
15 March, 04:23

The following experiment is carried out in a physiology lab. Red blood cells are placed in different solutions: distilled water, 0.45% saline, 0.9% saline, 5% urea, and 5% glucose. The molecular mass for each molecule is given: NaCl = 58.44 gm/mole; urea = 60.06 gm/mole; glucose = 180.16 gm/mole.

For each of the solutions used, calculate the osmolarity. To do this, you will need to convert solutions given in percents to osmolarity. A 0.45% saline solution has 0.45 gm/100 mL NaCl, or 4.5 gm/L. The same is true for the other molecules.

Fill in the osmolarity of each solution to the nearest integer using the choices provided.

Distilled water = ... mOsm

0.45% saline = ... mOsm

0.9% saline = ... mOsm

2.0% urea = ... mOsm

5% glucose = ... mOsm

+3
Answers (1)
  1. 15 March, 06:00
    0
    Osmolarity of distilled water = 0

    Osmolarity of NaCl=154 Osm

    Osmolarity of NaCl=0.308 Osm

    Osmolarity of urea=1.66 Osm

    Osmolarity of urea=0.66 Osm

    Osmolarity of glucose=0.556 Osm

    Explanation:

    osmolarity is calculated by the following expression:

    O=2*molarity of salt

    Osmolarity of distilled water = 0

    Osmolarity of 0.45% NaCl:

    moles of NaCl=weight/molecular weight=0.45/58.44=7.7x10^-3 moles

    Molarity of NaCl=moles of NaCl/Volume of solution=7.7x10^-3/0.1=0.077 M

    Osmolarity of NaCl=2*0.077=154 Osm

    Osmolarity of 0.9% NaCl

    moles of NaCl=0.9/58.44=0.0154 moles

    Molarity of NaCl=0.0154/0.1=0.154 M

    Osmolarity of NaCl=2*0.154=0.308 Osm

    Osmolarity of 5% urea:

    moles of urea=5/60.06=0.083 moles

    Molarity of urea=0.083/0.1=0.83 M

    Osmolarity of urea=2*0.83=1.66 Osm

    Osmolarity of 2% urea:

    moles of urea=2/60.06=0.033 moles

    Molarity of urea=0.033/0.1=0.33 M

    Osmolarity of urea=2*0.33=0.66 Osm

    Osmolarity of 5% glucose:

    moles of glucose=5/180=0.0278 moles

    Molarity of glucose=0.0278/0.1=0.278 M

    Osmolarity of glucose=2*0.278=0.556 Osm
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The following experiment is carried out in a physiology lab. Red blood cells are placed in different solutions: distilled water, 0.45% ...” in 📙 Biology if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers