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21 November, 20:25

An male animal has a genotype of AaBB. The number of different gene combinations that would be found in the sex cells/sperm of this animal would be:

a) 1

b) 2

c) 4

d) 6

e) 8

+2
Answers (1)
  1. 21 November, 21:30
    0
    B

    Explanation:

    Using a Punnett Square, you find that the outcomes are AB, AB, aB, and aB. There are only two unique genotypes here, so the answer is 2.
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