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21 February, 08:02

Sixty flowering plants are planted in a flowerbed. forty of the plants are red-flowering homozygous dominant. twenty of the plants are white-flowering homozygous recessive. the plants naturally pollinate and reseed themselves for several years. in a subsequent year, 178 red-flowered plants, 190 pink-flowered plants, and 52 white-flowered plants are found in the flowerbed. use a chi-square analysis to determine if the population is in hardy-weinberg equilibrium

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  1. 21 February, 09:47
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    The flowering population is in Hardy Weinberg equilibrium.

    Step by Step Explanation:

    Total initial population size = 60

    As both the populations are homozygous so the frequency of alleles will be,

    P = 80/120 = 0.66

    q = 40/120 = 0.33

    The predicted frequencies for genotypes once the population has reached Hardy-Weinberg

    p2 = 0.4356

    2pq = 0.4356

    q2 = 0.1089

    The number of plants with each type of flower in a papulation of 420 is,

    Homozygous dominant = 185

    heterozygous = 185

    Homozygous recessive = 50

    Chi square analysis:

    The observed values for red-flowered plants, pink-flowered plants, and white-flowered plants are not significantly different from the expected values predicted by Hardy Weinberg equilibrium.

    Phenotype observed (o) expected (e) (o-e) 2/e

    Red 178 185 0.26

    Pink 190 185 0.135

    White 52 50 0.08

    chi-square = 0.474

    With 2 degree of freedom this chi-square gives a p value of 0.7 - 0.8, which is not significant.
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