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5 July, 14:34

in a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of the population has short stems, calculate the percentage of the population that is expected to be heterozygous (Ss).

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  1. 5 July, 16:06
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    We solve the problem using the Hardy-Wineberg equation.

    Let us start with the homozygous recessive percentage first,

    q² = 35/100 = 0.35

    We have the frequency for short stem (s) as q = √0.35 = 0.59

    Solving for the frequency of long stem (S) by using the fact that,

    p + q = 1

    ∴ p = 1 - q = 1 - 0.59 = 0.41

    So the long stem (S) has a frequency of 0.41.

    Now we can calculate 2pq which is the heterozygous alleles (Ss) frequency.

    ∴ 2pq = 2 x 0.59 x 0.41 = 0.48

    Hence 48% of the population is heterozygous for long stem.
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