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13 August, 22:44

A homozygous recessive parent for no freckles's and heterozygous parent for freckles have a what is the of a these parent is having a child with no freckless

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  1. 14 August, 01:38
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    50% chance or 1/2.

    Explanation:

    Let's denote the no freckles allele with f and the freckles allele with F since it is dominant over the no freckles trait.

    One parent is homozygous recessive: ff

    The other parent is heterozygous (So they have freckles) : Ff

    Let's do a Punnett Square to calculate the possibility of the offspring having freckles or not. (The Punnett Square may not be perfect)

    | F f

    f | Ff ff

    f | Ff ff

    Two of the offspring have Ff, meaning they will have freckles, and two of the offspring have ff, meaning they will not have freckles.

    2 out of 4 don't have freckles, which means a 50% chance or 1/2.
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