During the early stages of an enzyme purification protocol, when cells have been lysed but cytosolic components have not been separated, the reaction velocity versus substrate concentration is sigmoidal. As you continue to purify the enzyme, the curve shifts to the right. Explain your results.

Question

Biology

Azul Larson

24 November, 23:43

During the early stages of an enzyme purification protocol, when cells have been lysed but cytosolic components have not been separated, the reaction velocity versus substrate concentration is sigmoidal. As you continue to purify the enzyme, the curve shifts to the right. Explain your results.

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Answers (2)

Know the Answer?

Brody Casey · Answer 1

The enzyme is an allosteric enzyme that has double-displacement, thereby being purified a heterotrophic activator

Explanation:

The term heterotrophic activator refers to when the substrate and the regulator in a chemical reaction correspond to different molecules

Karlee Fletcher · Answer 2

This is an allosteric enzyme showing a double-displacement mechanism

(ping-pong mechanism) and during purification a heterotrophic activator is purified away.

Explanation:

Double-displacement mechanism involves the reaction in which no ternary complex is formed. An enzyme-substrate complex forms, a product leaves the complex, altered enzyme forms a second complex with another substrate molecule, and the second product leaves, regenerating the enzyme.

So, during the early stages of an enzyme purification protocol, when cells have been lysed but cytosolic components have not been separated, the reaction velocity versus substrate concentration is sigmoidal. As you continue to purify the enzyme, the curve shifts to the right, because of an allosteric enzyme showing a double-displacement mechanism and during purification, a heterotrophic activator is purified.