A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

Question

Biology

Noah Young

24 April, 23:24

A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

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Answers (1)

Know the Answer?

Carmen Todd · Answer 1

The answer is 314.6 K

Gay-Lussac’s law:

PV = kT

P - pressure

V - volume

T - temperature

k - constant

k = PV/T = P1 * V1 / T1 = P2 * V2 / T2 = ...

P1 * V1 / T1 = P2 * V2 / T2

P1 = 1.1 atm

V1 = 7 L

T1 = 285 K

P2 = 1.1 atm - 0.6 atm = 0.5 atm

V2 = 7 L + 10 L = 17 L

T2 = ?

1.1 * 7 / 285 = 0.5 * 17 / T2

7.7 / 285 = 8.5 / T2

T2 = 8.5 * 285 / 7.7

T2 = 314.6 K