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5 September, 11:20

In a population of grasshoppers, the color green (G) is completely dominant over the color brown (g). If 23% of the population is brown, calculate the percentage of the population that is expected to be heterozygous

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  1. 5 September, 12:26
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    The answer is 49.92%

    Let's use the Hardy-Weinberg principle:

    p + q = 1

    p ² + 2pq + q² = 1

    where:

    p - the frequency of dominant allele G

    q - the frequency of recessive allele g

    p² - the frequency of homozygous dominant individuals GG with colour green

    2pq - the frequency of heterozygous individuals Gg with colour green

    p² - the frequency of homozygous recessive individuals gg with color brown

    23% of the population is brown: p² = 23% = 0.23

    p = √ (p²) = √0.23 = 0.48

    p = 0.48

    p + q = 1

    0.48 + q = 1

    q = 1 - 0.48 = 0.52

    The percentage of the population that is expected to be heterozygous is 2pq:

    2pq = 2 * p * q = 2 * 0.48 * 0.52 = 0.4992 = 49.92%
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