What is the ph of a substance with a hydroxide{OH] of 10-6

POH = - log[OH^-]

pOH = - log[10^-6]

pOH = - (-6)

pOH = 6

knowing the ionization equation between pH and pOH in a solution at T = 25 degrees Celsius.

pH + pOH = 14

pH = 14 - pOH

pH = 14 - (6)

pH = 8.

I believe the pH of a substance with 10^-6 M of OH, would be 8.