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20 February, 17:24

How many moles of MgCl2 are there in 321 g of the compound?

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  1. 20 February, 17:37
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    MgC23 = 24.31 + (2 x 35.45) = 95.21 g/mol

    340 g Mg C12 (1 mol / 95.21 g) = 3.57 mol MgC12
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