If it takes 16.73 mL of a 0.253 M LiOH solution to neutralize10.00 mL of HBr, what is its concentration?

The neutralization reaction is written as:

LiOH + HBr = LiBr + H2O

0.253 mol LiOH / L solution (.01673 L solution) (1 mol HBr / 1 mol LiOH) = 4.233 x 10^-3 mol HBr

Concentration of HBr solution = 4.233 x 10^-3 mol HBr /.01 L solution = 0.423 M HBr solution