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A metal alloy bolt is initially at 100.0°C. It is dropped into a coffee cup calorimeter containing 50.0 g of water at a temperature of 20.0°C. After stirring, the final temperature of both bolt and water is 25.0°C. Assuming no heat losses, and that the specific heat (capacity) of water is 4.18 J / (g ∙ K), what is the heat capacity of the bolt in J/K?

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  1. Today, 02:06
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    the heat capacity of the bolt is 13.9 J/K

    Explanation:

    J/K is short of " joule per kelvin", is the international system unit of heat capacity

    heat energy = (mass of substance) (specific heat) (change in temperature)

    Q = mc∆T

    Q = heat energy (Joules, J)

    m = mass of a substance (kg)

    c = specific heat (units J/kg∙K)

    ∆ is a symbol meaning "the change in"

    ∆T = change in temperature (Kelvins, K)

    Heat gained by water = heat lost by copper = Q = mC∆T = (50 g) (4.18 J/g/deg) (5 deg) = 1045 J = C x ∆T

    C = 1045 J/75 = 13.9 J/deg
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