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20 September, 13:31

A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and hold 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25 to produce and the cremes cost $0.45 to produce, how many of each should be in the box to yield a profit of $3 dollars?

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  1. 20 September, 14:54
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    Number of caramels = 20

    number cremes = 30 - 20 = 10

    Explanation:

    Data provided in the question:

    Selling cost of each box = $12.50

    Number of pieces of candies held in a box = 30

    Cost of producing caramel = $0.25

    Cost of producing cremes = $0.45

    Now,

    let the number of caramels be 'x'

    Thus,

    Number of cremes = 30 - x

    Profit = Selling price - Cost

    3 = $12.50 - [ 0.25x + 0.45 (30 - x) ]

    or

    [ 0.25x + 0.45 (30 - x) ] = 12.50 - 3

    or

    0.25x + 13.5 - 0.45x = 9.50

    or

    -0.20x = 9.50 - 13.5

    or

    -0.20x = - 4

    or

    x = 20

    Hence,

    Number of caramels = 20

    number cremes = 30 - 20 = 10
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