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14 August, 13:49

A stadium has 54 comma 000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1 comma 154 comma 000 from each sold-out event. How many seats does each section hold?

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Answers (2)
  1. 14 August, 15:15
    0
    section A = 27,000 seats

    section B = 14,500 seats

    section C = 12,500 seats
  2. 14 August, 15:52
    0
    Section A = $27,000

    Section B = $14,800

    Section C = $12,200

    Explanation:

    In this question, we have to assume the things

    Like - Let the number of seats in section B be X and, in Section C be Y

    So, Section A = Section B + Section C

    That means, Section A = X + Y

    And, Section A + Section B + Section C = $54,000

    Means, X + Y + X + Y = $54,000

    2X + 2Y = $54,000

    So, X + Y = $27,000

    And, the other equation is 20X + 15Y = $1,54,000 - 25 * 27,000

    So, the both equation is

    X + Y = $27,000

    20X + 15Y = $479,000

    Now multiply 20 in equation 1

    So,

    20X + 20Y = $540,000

    20X + 15Y = $479,000

    Now deduct the equation 1 from equation 2

    So, the value would equal to

    5Y = $61,000

    Y = $12,200

    X = $27,000 - $12,200 = $14,800

    And, the Section A = X + Y = $27,000
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