An air-filled pipe is found to have successive harmonics at 1085 HzHz, 1395 HzHz, and 1705 HzHz. It is unknown whether harmonics below 1085 HzHz and above 1705 HzHz exist in the pipe. What is the length of the pipe

0.55m

Explanation:

the successive harmonic frequencies are,

f = 1085Hz

f¹ = 1395Hz

f² = 1705Hz

fundamental frequency = 2F = f¹ - f

F = (f¹ - f) / 2

F = (1395-1085) / 2

F = 310/2

=155Hz

F = V/4L

Where V = velocity of sound in air = 343m/s

l=length of pipe

L = V/4F

=343 / (4 * 155)

=343/620

=0.553m