Sam makes a deposit at the bank which is comprised of $5, $10, and $20 bills. If the number of $5 bills is three more than the number of $10 bills, the number of $20 bills is half the number of $5 bills, and his total deposit is $270, how many bills of each type did he deposit?

Number of $5 bills = 12

Number of $10 bills = 9

Number of $20 = 6

Explanation:

Giving the following information:

Total deposit = $270

$5 bills are three more than the number of $10 bills.

The number of $20 bills is half the number of $5 bills.

x1 = number of $5 bills

x2 = number of $10 bills

x3 = number of $20 bills

x1=3+x2

x3=x1/2

The function to calculate the number of bills is:

Total number of bills = (3+x2) * $5 + x2*$10 + (x1/2) * $20

n $x1 n $x2 n $x3

4 20 1 10 2 40 70

5 25 2 20 2,5 50 95

6 30 3 30 3 60 120

7 35 4 40 3,5 70 145

8 40 5 50 4 80 170

9 45 6 60 4,5 90 195

10 50 7 70 5 100 220

11 55 8 80 5,5 110 245

12 60 9 90 6 120 270

x1 = 12

x2 = 9

x3=6