Ask Question
30 July, 22:37

Cindy wishes to arrange her coins into $X$ piles, each consisting of the same number of coins, $Y$. Each pile will have more than one coin and no pile will have all the coins. If there are 13 possible values for $Y$ given all of the restrictions, what is the smallest number of coins she could have?

+5
Answers (1)
  1. 31 July, 01:58
    0
    The smallest number of coins she could have is 4

    Explanation:

    With this Cindy respect all of the restrictions; Piles have the same number of coins, each pile will have more than one coin and no pile will have all the coins. That means X (piles) should be bigger than 1, and Y (coins in the piles) should also be bigger than 1. And there is no specification about the values of Y.

    Therefore with a minimum of 4 coins, Cindy can do 2 piles of 2 coins each.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Cindy wishes to arrange her coins into $X$ piles, each consisting of the same number of coins, $Y$. Each pile will have more than one coin ...” in 📙 Business if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers