A party mix is made by adding nuts that sell for $2.50 per kg to a cereal mixture that sells for $11 per kg. how much of each should be added to obtain 30 kg of a mix that will sell for $1.50 per kg?

10 kg of nuts 20 kg of cereal I am going to assume that there's a typo in the question. There is no possible combination of two items where one costs $2.50/kg and the other costs $11.00/kg where the result is worth $1.50/kg. But if the cereal actually costs $1/kg, then there is a solution. That is the solution I'll show. N = amount of nuts (30-N) = amount of cereal The overall equation is 2.50N + 1.00 (30-N) = 30*1.50 Now solve for N. First distribute the 1 2.50N + 30 - N = 30*1.50 2.5N + 30 - N = 45 1.5N + 30 = 45 1.5N = 15 N = 10 So you need 10 kg of nuts and 30-10 = 20 kg of cereal. Let's verify the results 10*2.50 + 20 * 1.00 = 25.00 + 20.00 = $45.00 $45.00 / 30 kg = $1.50/kg