Use the following statement to answer parts a) and b). Five hundred raffle tickets are sold for $3 each. One prize of $100 is to be awarded. Winners do not have their ticket costs of $3 refunded to them. Raul purchases one ticket. a) Determine his expected value. b) Determine the fair price of a ticket. a) His expected value is $ nothing. (Type an integer or a decimal.)

A) he would make a loss of $2.79 of his ticket purchase hence the expected value of the ticket will be $3 - $2.79 = $0.21

B) fair price of a ticket = $0.20

Explanation:

A) The expected value

The variables are : winner prize = + $100 and - $3 (not refunded)

The probability of winning the prize = 1/500 and 499/500 for not winning

therefore the expected value E (x) would be

= 100 * 1/500 + (-3) * 499/500

= $0.2 - $2.99

= - $2.79 he would make a loss of $2.79 of his ticket purchase hence the expected value of the ticket will be $3 - $2.79 = $0.21

B) the fair price of the ticket would be

lets assume the fair price to be "y"

The random variables are $100 and - y

the corresponding probabilities of winning and not wining are : 1/500 and 499/500

= (100 * 1/500) + (-y * 499/500) = 0

= 100/500 - 499 y/500 = 0

= 100 - 499 y = 0

therefore y = 100 / 499 = $0.20 fair value of the ticket

A.) - 2.8

B.) 0.2

Explanation:

Ticket price = $3

Winning price = $100

Probability of the winning (Pwin) = (1/500)

Probability of the not winning (Ploss) = [ 1 - (1/500) ] = 499/500

Net income if Raul wins (Nwin) = $100 - $3 = $97

Net loss if Raul loss (Nloss) = - $3

A.) Calculation of Expected value

(Pwin * Nwin) + (Ploss * Nloss)

((1/500) * 197) + ((499/500) * - 3)

0.194 - 2.994 = - 2.8

B.) Calculation of Fair Value;

Cost of ticket + Expected value

3 - 2.8 = 0.2