What is the mass occupied by 44.8 l of nitrogen (n2 ) at standard conditions?

Data Given:

Volume = V = 44.8 L

Standard Pressure = P = 1 atm

Standard Temperature = T = 273 K

According to Ideal Gas Equation,

P V = n R T

Solving for n,

n = P V / R T

Putting values,

n = (1 atm * 44.8 L) : (0.0821 atm. L. mol⁻¹. K⁻¹ * 273 K)

n = 1.99 mol

Now, calculating for mass,

n = Mass / M. mass

Or,

Mass = n * M. mass

Mass = 1.99 mol * 28 g. mol⁻¹

Mass = 55.72 grams