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11 February, 21:44

Determine the volume occupied by 0.582 mol of a gas at 15 degrees Celsius if the pressure is 81.8 KPA?

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  1. 12 February, 00:56
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    Ideal gas law:

    PV=nRT ⇒V = (nRT) / P

    P=pressure

    V=volume

    n=number of moles

    R=gas constant = 0.082 atm. litres/ºK mol

    T=temperature

    P=81.8 Kpa * (1 atm / 101.325 Kpa) ≈0.81 atm.

    n=0.582 moles

    T=15+273.15=288.15ºK

    R=0.082 atm. litres/ªKmol

    V = (0.582 moles*0.082 atm l/ºKmol * 288.15ºK) / 0.81 atm≈17.04 litres.

    Sol: 17.04 litres.
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