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2 September, 19:38

Sodium metal and water react to form hydrogen and sodium hydroxide. if 17.94 g of sodium react with water to form 0.78 g of hydrogen and 31.20 g of sodium hydroxide, what mass of water was involved in the reaction

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  1. 2 September, 22:02
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    The mass of water involved in reaction is calculated as follows

    in a reaction mass of reactants should = mass of products

    mass of product = mass of hydrogen + mass of sodium hydroxide

    = 0.78 g + 31.20 g = 31.98 grams

    mass of reactant = mass of sodium metal + mass of water

    let the mass of water be represented by y

    =17.94g + y = 31.98 g

    like terms together

    y=31.98 g - 17.94 g = 14.04 grams of water
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